9x^2-148x+64=0

Solution for 9x^2-148x+64=0 equation:

9x^2-148x+64=0

a = 9; b = -148; c = +64;
Δ = b2-4ac
Δ = -1482-4·9·64
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-148)-140}{2*9}=\frac{8}{18}
=4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-148)+140}{2*9}=\frac{288}{18}
=16
$